Question

How many liter of 64gm of methane? Write the total number of nucleons present in methane

Answer 1

Answer:

64 NA = 64 × 6.023 × 10²³ nucleons.

Explanation:

given mass = 64g

molar mass of methane (CH4) = 12 + 4 = 16

no. of moles = given mass / molar mass

= 64/16

= 4 moles.

moles = no. of particles / 6.023 × 10²³

no.of particles = no.of nucleons

no. of nucleons = no. of protons + neutrons

no. of protons in carbon = 6

no. of neutrons in carbon = 6

no. of protons in 4 hydrogen = 4 × 1 = 4

no. of neutrons in 4 hydrogen = 4 × 0 = 0

so total no. of nucleons in one molecule of methane = 6 + 6 + 4 = 16

moles = no. of particles / 6.023 × 10²³

4 = no. of particles / 6.023 × 10²³

4 × 6.023 × 10²³× 16 = no. of nucleons in 4 moles.

64 × 6.023 × 10²³ nucleons.

hope it helped.