Chemistry, asked by Favourichlife372, 11 months ago

How many liter of oxygen at stp is required to burn 60 g c2h6?

Answers

Answered by duadevansh58
0

Answer:C2H6 +7/2 O2———->2CO2  + 3H2O

Molecular mass of ethane C2H6 = [2x12+6x1]=30u

Molar mass of C2H6=30g

30 g of ethane needs  3.5 moles of O2.

1 mole of any gas occupies 22.4litres.

3.5 moles occupy

=3.5x22.4/1

=78.4L

For 60g of ethane we need= (78.4/30)x 60=156.8 L of oxygen.

Explanation:

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