How many liters in 7 g of H2
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AT STP, 1 mole of H2 gas i.e. 2 grams (1 mole) of it occupies 22.4 litresThus, 0.5 grams of it will occupy 5.6 litres at STP.
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1 mole of H2 molecules = 6.023 X 10 ^23 (H2 molecule)= 22.4 liters of volume of H2 gas
1 mole of H2 molecules = 1 mole of H atom +1 mole of H atom (because there are two atoms of hydrogen in hydrogen gas)
1 mole of H2 molecules = 1 mole of H atom +1 mole of H atom
1 mole of H2 molecules = 1g + 1g = 2g
22.4 liters of H2 gas = 2g
1 liter of H2 gas = 2/22.4 g
1 liter of H2 gas = 0.0893 g
1 liter volume of H2 gas contains 0.0893 g of H2 gas (in terms of mass)
I have gave of 1 liter you find of 7 liters
If you will copy the answer in notebook then when you will try to solve
1 mole of H2 molecules = 1 mole of H atom +1 mole of H atom (because there are two atoms of hydrogen in hydrogen gas)
1 mole of H2 molecules = 1 mole of H atom +1 mole of H atom
1 mole of H2 molecules = 1g + 1g = 2g
22.4 liters of H2 gas = 2g
1 liter of H2 gas = 2/22.4 g
1 liter of H2 gas = 0.0893 g
1 liter volume of H2 gas contains 0.0893 g of H2 gas (in terms of mass)
I have gave of 1 liter you find of 7 liters
If you will copy the answer in notebook then when you will try to solve
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