Question

How many liters of 3% alcohol solution should be mixed with a 6lot of 30% alcohol solution so as to get a 12% solution govt adda?

Answer 1

Let the solution with 3% alcohol concentration be x litres

The amount of alcohol is :

0.03x litres

From the 6 litres the amount of alcohol is :

30/100 × 6 = 1.8 litres

The new solution will have :

(0.03x + 1.8) litres of alcohol.

This is 12% of the total solution.

The total solution is :

(x + 6) litres

12% of this is :

0.12 × (x + 6) = 0.12x + 0.72

0.12x + 0.72 = 0.03x + 1.8

0.12x - 0.03x = 1.8 - 0.72

0.09x = 1.08

x = 12

The answer is 12 litres