How many liters of a 6.0M solutions of acetic acid ch3cooh contain 0.0030 moles of acetic acid
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Given:
The molarity of the acetic acid solution = 6M
To Find:
The number of liters of the solution that contain 0.0030 moles of acetic acid
Solution:
0.005 liters of 6.0 M solution of acetic acid contains 0.0030 moles of acetic acid.
We know that the molarity of a solution gives the number of moles of solute that are present in 1 L of the solution.
⇒ In the 6M solution, 6 moles of CH₃COOH are present in 1 L of the given solution.
So 1 mole of CH₃COOH is present in 1/6 L of the solution.
Multiplying both sides by 0.0030,
It can be concluded that 0.0030 moles of acetic acid are present in 0.0030 / 6 L of the solution
= 1/200 L
= 0.005 liters
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