Question

how many liters of liquid ccl4 (d = 1.5 g/cc ) must be measured out to contain 1 * 10 rase to the power 25 cl atoms

Answer 1

1*10^25 ÷ NA
= 166.03

ccl4 have 4 atoms of chlorine, hence
and volume = mass / density

mass = 166.04*35.5=589.4

volume= 589.4÷1.5
=392.9cc=392.9 ml
= 0.3929L

P.S. - Answer can vary because of approximate calculation.