how many liters of liquid ccl4 (d = 1.5 g/cc ) must be measured out to contain 1 * 10 rase to the power 25 cl atoms
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1*10^25 ÷ NA
= 166.03
ccl4 have 4 atoms of chlorine, hence
and volume = mass / density
mass = 166.04*35.5=589.4
volume= 589.4÷1.5
=392.9cc=392.9 ml
= 0.3929L
P.S. - Answer can vary because of approximate calculation.
= 166.03
ccl4 have 4 atoms of chlorine, hence
and volume = mass / density
mass = 166.04*35.5=589.4
volume= 589.4÷1.5
=392.9cc=392.9 ml
= 0.3929L
P.S. - Answer can vary because of approximate calculation.
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