Question

. How many liters of milk solution which contain milk
and water in the ratio 5:3 is added to 52 liters of another
milk solution which contain milk to water in the ratio 3
: 7 to get the ratio of water to milk 5: 4.​

Answer 1

Answer:

Let x liter of milk solution which contain milk and water in the ratio 5 :3 is added to 42 liters of another milk solution which contain milk to water in the ratio 3:7 to get the ratio of water to milk 5:4.

⇒ \frac{5}{8}\times 42 + \frac{3}{10} \times x = \frac{5}{9} ( 42 + x)

8

5

×42+

10

3

×x=

9

5

(42+x)

\frac{210}{8} + \frac{3x}{10} = \frac{210+5x}{9}

8

210

+

10

3x

=

9

210+5x

\frac{1050}{40} + \frac{12x}{40} = \frac{210+5x}{9}

40

1050

+

40

12x

=

9

210+5x

\frac{1050+12x}{40} = \frac{210+5x}{9}

40

1050+12x

=

9

210+5x

9450+108x = 8400+200x9450+108x=8400+200x

9450+108x -200x = 8400-94509450+108x−200x=8400−9450

-92x=-1050−92x=−1050

x=11.4130434783\approx 11.413x=11.4130434783≈11.413

Hence, Required quantity of milk solution which contain milk and water in the ratio 5 :3 is 11.413 liter.