How many liters of water will a hemisphere bowl of radius 100cm contain and find its csa
Answers
Answer:
Volume = 44/21 m^3
C.s.a = 44/7 m^2
Step-by-step explanation:
Litres of water the hemisphere bowl will contain = volume of the hemispherical bowl
Radius = 100cm = 1m
Volume of a hemisphere = 2/3×pi×r^3
Volume = 2/3×22/7×1×1×1
Volume = 44/21 m^3
C. S. A of hemisphere = 2×pi×r^2
C.s.a = 2×22/7×1×1
C.s.a = 44/7 m^2
The bowl will hold 44/21 m^3 of water and it's c.s.a is 44/7 m^2
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Given :----
- radius of Hemisphere = 100cm.
To Find :---
- Volume of Hemisphere bowl ?
- CSA of Hemisphere bowl ?
Formula used :-----
- Volume of Hemisphere = 2/3 πr³
- CSA of Hemisphere = 2πr²
- 100cm = 1m .
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Solution :------
We can say that, radius = 100cm = 1m .
Now , putting values in above told formula we get,
→ Volume of Hemisphere bowl = 2/3 × 22/7 × (1)³ = (44/21)m³
→ CSA of Hemisphere bowl = 2 × 22/7 × (1)² = (44/7)m²
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Hence, Volume of Hemisphere bowl will be (44/21)m³ and CSA of of Hemisphere bowl will be (44/7)m² .
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