Question

How many lithium atoms are present in a unit cell with edge length 3.5 A and density 0.53 g/cm -3 (Atomic mass of Li=694) * 1

Answer 1

Answer:

z=2

Explanation:

a=3.5

A

˚

, ρ=0.53g/cm

3

, M

A

=6.94, Z=?

ρ=

N

A

×a

3

Z×M

A

0.53=

6.023×10

23

×42.875×10

−24

Z×6.94

Z=2