Question

How many lithium atoms are present in a unit cell with edge length 3.5
˙
A
A˙
and density 0.53 g cm-3 ?
(A)2
(B)1
(C)4
(D)6

Answer 1

Answer:

Explanation:

How many lithium atoms are present in a unit cell with edge length 3.5

˙

A

A˙

and density 0.53 g cm-3 ?

(A)2

(B)1

(C)4

(D)6

Answer 2

Answer:

your answer is 2

Explanation:

the number of Li.atoms in a unit cell is 2 .

the density of the atom is given by the expression

density=(Zm/N(a^3)

here,Z is the number of atom in a cell unit,m is the molecular mass of the atom,N is the Avogadro's number,and a is edge length

plugging the values in the above equation

0.53=

z=2

therefore the number of atom in a unit cell of Li. is 2

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