how many litre CO2 at ntp required to complete composition of one mole c5h10
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2 C5H10 + 15 O2 = 10 CO2 + 10 H2O2mol c5H10-15MOL O21MOLC5H10->15/2MOL O215/2=V/22.4V=7.5*22.4=168L of O2
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