How many litre O, at STP is required for complete combustion of 1 mole C5H10?
A
336 L
B
84 L
C
168 L
D
252 L
KH
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Answer:
C 168 L
Explanation:
2 Mol of C5H10 ----> 15mol of O2
1 Mol of C5H10 -----> 15/2 Mol of O2
Now,
Using the formula Mol = Volume in litres/22.4
15/2 = Volume in litres/22.4
Volume in litres = 22.4×15/2
Volume in Litres = 168 L
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