Question

how many litre of 2M H3AsO4 require to prepare 4 litres of 1M H3AsO4 plzz ans quickly​

Answer 1

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Answer 2

Given - Molarity of first solution - 2M

Molarity of second solution - 1M

Volume of second solution - 4 litres

Find - Volume of first solution.

Solution - To find volume of first solution, we will use the formula M1V1 = M2V2, where M1 and M2 are molarity of first and second solution and V1 and V2 are volume of first and second solution.

Keeping the values in equation-

2*V1 = 1*4

V1 = 4/2

V1 = 2 liters.

Hence, 2 liters of 2M H3AsO4 is required in given conditions.