how many litre of oxygen at STP is required to burn 60 gram C2H6
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mass of 1 mole of c2h6 = 12+12+6= 30 gm
hence no. of moles in 60 gm c2h6 = 2 moles
2 c2h6 reacts with 7O2 to burn
hence 2 mole of c2h6 will react with 7 moles of oxygen
volume 7 mole oxygen at stp = 7 * 22.4 ( molar volume)
= 156.8 litres
hence no. of moles in 60 gm c2h6 = 2 moles
2 c2h6 reacts with 7O2 to burn
hence 2 mole of c2h6 will react with 7 moles of oxygen
volume 7 mole oxygen at stp = 7 * 22.4 ( molar volume)
= 156.8 litres
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