Chemistry, asked by AnandiSiri1909, 10 months ago

How many litres of 0.1Normality solution will be prepared by dissolving 56g KOH in water?

Answers

Answered by sne27gha
1

Answer:

Explanation:

normality = 56 x 1000/(56 x volume)

u get 10 ^4

Answered by MrGamographer
2

Answer:

10 Litres

Explanation:

Normality = Molarity x Valency Factor

Arranging according to the Above Equation

0.1 = 56÷{M.Wt(KOH) x Volume of Solvent} x V.F. Of KOH

0.1 = 56/56 x Vol(in Litre) x 1

0.1 = 1/Vol

Volume comes out to be 10 Litres

Similar questions