Question

How many litres of co2 at stp will be formed when 0.01 mol of H2SO4 reacts with excess of Na2Co3

Answer 1

Reaction between the H₂SO₄ and Na₂CO₃ is

Na₂CO₃ + H₂SO₄ ---------→ Na₂SO₄ + H₂O + CO₂↑

From the Reaction,
1 mole of H₂SO₄ produces 1 mole of CO₂.
∴  0.01 mole of H₂SO₄ produces 1 × 0.01 = 0.01 mole of CO₂.

Now, we know, 
1 mole of any gas at S.T.P. occupies the volume of 22.4 liter.
∴ 1 mole of CO₂ at S.T.P. occupies the volume of 22.4 liter.
∴ 0.01 mole of CO₂ at S.T.P. occupies the volume of 22.4 × 0.01 liter 
= 0.224 liter = 224 ml.


0.224 l or 224 ml of the CO₂ at S.T.P. will be produced in the Reaction.


Hope it helps.

Answer 2

hey mate.....☺️☺️☺️☺️

Reaction between the H₂SO₄ and Na₂CO₃ is

Na₂CO₃ + H₂SO₄ ---------→ Na₂SO₄ + H₂O + CO₂↑

From the Reaction,

1 mole of H₂SO₄ produces 1 mole of CO₂.

∴  0.01 mole of H₂SO₄ produces 1 × 0.01 = 0.01 mole of CO₂.

Now, we know, 

1 mole of any gas at S.T.P. occupies the volume of 22.4 liter.

∴ 1 mole of CO₂ at S.T.P. occupies the volume of 22.4 liter.

∴ 0.01 mole of CO₂ at S.T.P. occupies the volume of 22.4 × 0.01 liter 

= 0.224 liter = 224 ml.

0.224 l or 224 ml of the CO₂ at S.T.P. will be produced in the Reaction.

Brain list pls❤️❤️❤️

@toshika

#follow me#