Question

How many litres of milk can a hemispherical bowl of diameter 10.5 cm hold?
​

Answer 1

Step-by-step explanation:

Given data

diameter =10.5 cm

Volume of the bowl which is hemisphere =

3

2

πr

2

→(1)

where r→ radius

r=

2

d

=

2

10.5

=5.25 cm→(2)

Substituting (2) in (1)

V=

3

2

×

7

22

×5.25×5.25×5.25

=303.1875 cm

3

(π=

7

22

)

The answer must be converted into lives as it was asked to be calculated in litre

V=303.1875×

1000

1

litre

=0.3031875 litre

=0.303 litre (approx) [∴ 1 cm

3

=

1000

1

litre]

Hence, the hemispherical bowl can hold 0.303 litre.

Answer 2

Given :

$\sf{}$

Diameter (d) = 10.5 cm

$\sf{}$

To find :

$\sf{}$

Litres of milk the hemispherical bowl can hold

$\sf{}$

Formula used :

$\sf{}$

$\sf{Volume = \dfrac{2}{3} \: \pi \: {r}^{3} }$

$\sf{}$

Solution :

$\sf{}$

$\sf{First \: , we \: have \: to \: find \: the \: radius,} \\ \sf{As \: we \: all \: know ,} \\ \\ \implies\sf{r = \dfrac{d}{2} } \\ \\ \: \: \: \: \implies\sf{r = \dfrac{10.5}{2} } \\ \\ \: \: \: \implies\sf{r =5.25 \: cm}$

$\sf{}$

$\implies \sf{Volume \: of \: bowl = \dfrac{2}{3} \: \pi \: {r}^{3} } \: \: \: \: \: \: \: \: \: \\ \\ \implies \sf{ \dfrac{2}{3} \times \frac{22}{7} \: \times 5.25 \times 5.25 \times 5.25} \\ \\ \implies \sf{303.1875 \: {cm}^{3} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies \sf{303.1875 \times \dfrac{1}{1000 \:} \: litres } \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies \sf{0.3031875 \: (litres)} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies \sf{0.303 \: litres \: (approximately)} \: \: \: \\ \\ \sf{The \: hemispherical \: bowl \: can \: hold \: 0.303 \: litres.}$