Question

How many litres of milk can a hemispherical bowl of diameter 10.5 cm hold?
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Answer 1

$\large \color{magenta} \bold{Given,} \\ \\ \sf \: Diameter \: = \: 10.5 \: cm \: \: | \: Radius \: = \: \frac{Diameter}{2} \: \: | \: Radius \: = \: \frac{10.5}{2} \: \: | \: Radius \: = \: 5.25 \\ \\ \color{red} \boxed{ \sf \: Volume_{(hemisphere)} \: = \: \frac{2}{3} \pi \: {r}^{3}} \\ \\ \sf \: Volume \: = \: \frac{2}{3} \times \frac{22}{7} \times {5.25}^{ 3} \\ \\ \sf \: Volume \: = \: 303.18 \: {cm}^{3} \: \: \: \color{lime} \{approx \} \\ \\ \sf \: {\underline{Since \: the \: answer \: must \: be \: in \: litres}} \\ \\ \sf \: 1 {cm}^{3} = \frac{1}{1000} \: litres \\ \\ \sf \: = 303.18 \times \: \frac{1}{1000} \\ \\ \sf \: = 0.303 \: litres \: \: \{approx \} \\ \\ \sf \color{blue} \therefore \: The \: hemispherical \: bowl \: can \: contain \: 0.303 \: litres \: of \: milk.$

$\color{lime}\rule{200000000 pt}{2pt}$

Volume of cylinder = πr²h

T.S.A of cylinder = 2πrh + 2πr²

Volume of cone = ⅓ πr²h

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

Volume of cuboid = l × b × h

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

C.S.A of cube = 4a²

T.S.A of cube = 6a²

Volume of cube = a³

Volume of sphere = 4/3πr³

Surface area of sphere = 4πr²

Volume of hemisphere = ⅔ πr³

C.S.A of hemisphere = 2πr²

T.S.A of hemisphere = 3πr²