How many litres of o2 at S.T.P is required for complete combustion of 1 mole of C5H10
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At NTP conditions, 1 mole of a gas occupies 22.4 L of volume. So, for combustion of 1 kg of coal, we will require 83.333moles of oxygen (O2) which occupies 1.866×103 L of volume at NTP.
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At NTP conditions, 1 mole of a gas occupies 22.4 L of volume. So, for combustion of 1 kg of coal, we will require 83.333moles of oxygen (O2) which occupies 1.866×103 L of volume at NTP.
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