Question

how many litres of O2 at STP required for complete combustion of 11 gram of C3H8​

Answer 1

Answer:

28 litres

Explanation:

Molecular mass of c3h8=[(12×3)+(1×8)]

=[36+8].

=44gram

• c3h8 + 5O2 gives-3CO2+4H2O

Volume of 5O2=5×22.4litres

for complete combustion of 44g of C3H8 112 litres of O2 is required.

So,for complete combustion of 11g of C3H8:

112/44×11=28 litres