How many litres of oxygen at STP are required to burn completely 2.2 gram of butane (C4H10)
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Explanation:
The balanced chemical equation represting the reaction is
c3+h8+5o2 ➡️ 3co2+4h2o
1mole= 5❌ 22.4L
44g is stp
stoichiometry indicates that
1mole (44g) propane
=5❌22.4L o2at stp
2.2g propane = 5❌22.4❌2.2/44
5.6 litre o2 at stp.
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