Chemistry, asked by hijabgirl, 2 months ago

how many litres of Oxygen at stp will be required for complete combustion of 4.4g of propane.

Answers

Answered by snowelizabath233

3

Explanation:

the balanced chemical equation representing the reaction is

C3H8 + 5O2 ---> 3CO2 + 4H2O

1 mole (44g) propane

=5 × 22.4 L O2 at STP

• 2.2 g propane = 5 × 22.4 × 2.2 /44 litre O2

answer = 5.6 litre O2 at STP

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