how many litres of oxygen is needed to burn completely 2.2gram of propone(c3h8)
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Step-by-step explanation:
balence the equation of combustion of propane is
C3H8+502=3co2
+4H2O
At NTP
44g of propane requires 5*22.4L of oxygen for complete combustion
2.2g of propane requires 2.2*5*22.4/44
=5.6L
volume of oxygen required for complete combustion is 5.6l
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