How many litres of water must be added to 1 litre of an aqueous solution of hcl?
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Initial pH = 1, i.e. [H+] = 0.1 mole/litre
New pH = 2, i.e. [H+] = 0.01 mole/litre
In case of dilution: M1V1= M2V2
0.1 ×1 =0.01 × V2
V2= 10 litre.
Volume of water added = 9 litre.
Answered by
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♥╣[Hi Dear]╠♥
Initial pH = 1, i.e. [H+] = 0.1 mole/litre
New pH = 2, i.e. [H+] = 0.01 mole/litre
In case of dilution: M1V1 = M2V2
0.1 × 1 = 0.01 × V2
V2 = 10 litre
Volume of water added = 9 litre
(☞ ಠ_ಠ)☞Shivi
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