Question

how many litres of water will have to be added to 1125 litres of 45% solution of milk ,so that resulting mixture will contain at least 25% milk content.

Answer 1

HELLO DEAR,


LET x Litres Of Water Is Required To Be Added.

THEN, Total Mixture = ( x + 1125) litres

IT IS EVIDENT THAT THE AMOUNT OF ACID CONTAINED IN

THE RESULTING MIXTURE IS 45% OF 1125 litres.

THIS RESULTING MIXTURE WILL CONTAIN MORE Than 25% BUT LESS THAN 30% Acid Content.

30% of (1125 + x ) > 45% of 1125

And,

25% of (1125 + x ) < 45% of 1125


30 % of (1125 + x ) > 45% of 1125
$\frac{30}{100} (1125 + x) > \frac{45}{100} \times 1125 \\ = > 30(1125 + x) > 45 \times 1125 \\ = > 30 \times 1125 + 30x > 45 \times 1125 \\ = > x > \frac{15 \times 1125}{30} = 562.5$

25% of (1125 + x ) < 45% of 1125

$\frac{25}{100} (112 + x) < \frac{45}{100} \times 1125 \\ = > 25(1125 + x) > 45 \times 1125 \\ = > 25 x > 45 \times 1125 - 25 \times 1125 \\ = > x > \frac{20 \times 1125}{25} = 900$

562.5 < x < 900

THUS, The Required Number Of Litres of Water 

That Is To Be Added Will Have

To be More Than 562.5 But Less Than 900.


I HOPE ITS HELP YOU DEAR,
THANKS