How many lone pairs are present in ammonia?
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0 lone pair are present in ammonia.
Ammonia = NH3
N = 2 5
H = 1
So, N requires 3 electrons. Each H requires 1 electron. So, the octet will be completed by sharing and forming a covalent bond.
Ammonia = NH3
N = 2 5
H = 1
So, N requires 3 electrons. Each H requires 1 electron. So, the octet will be completed by sharing and forming a covalent bond.
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