How many m2 of tin would be required to line the inside of a rectangular tank on the sides and bottom if the inside dimensions of tank are 8m,, 5m, 4m,?
Answers
Answered by
3
Length of open plastic box =l=1.5 m
Breadth of open plastic box =b=1.25 m
Height of open plastic box =h=65 cm
Converting into meter
=65/100= 0.65 m
The area of the sheet required for making the open plastic box =lb+2bh+2hl
(Because it is open from the top)
=(1.5)(1.25)+2(1.25)(0.65)+2(0.65)(1.5)=1.875+1.625+1.95=5.45 m2
Cost of one sheet of 1 m2 = Rs 20
Cost of 5.45 m2 =20 X 5.45=Rs 109
Question 2
The length, breadth and height of a room are 5 m, 4 m and 3 m respectively. Find the cost of white washing the walls of the room and the ceiling at the rate of Rs 7.50 per m2
Solution:
The room dimension are given below
Length (l) of room = 5 m
Breadth (b) of room = 4 m
Height (h) of room = 3 m
Imp point:
It can be observed that four walls and the ceiling of the room are to be white-washed. The floor of the room is not to be white-washed.
Area to be white-washed
= Area of walls + Area of ceiling of room
= 2lh + 2bh + lb
= [2 × 5 × 3 + 2 × 4 × 3 + 5 × 4] m2
= (30 + 24 + 20) m2
= 74 m2
Now Cost of white-washing per m2 area = Rs 7.50
So Cost of white-washing 74 m2 area = Rs (74 × 7.50)
= Rs 555
Breadth of open plastic box =b=1.25 m
Height of open plastic box =h=65 cm
Converting into meter
=65/100= 0.65 m
The area of the sheet required for making the open plastic box =lb+2bh+2hl
(Because it is open from the top)
=(1.5)(1.25)+2(1.25)(0.65)+2(0.65)(1.5)=1.875+1.625+1.95=5.45 m2
Cost of one sheet of 1 m2 = Rs 20
Cost of 5.45 m2 =20 X 5.45=Rs 109
Question 2
The length, breadth and height of a room are 5 m, 4 m and 3 m respectively. Find the cost of white washing the walls of the room and the ceiling at the rate of Rs 7.50 per m2
Solution:
The room dimension are given below
Length (l) of room = 5 m
Breadth (b) of room = 4 m
Height (h) of room = 3 m
Imp point:
It can be observed that four walls and the ceiling of the room are to be white-washed. The floor of the room is not to be white-washed.
Area to be white-washed
= Area of walls + Area of ceiling of room
= 2lh + 2bh + lb
= [2 × 5 × 3 + 2 × 4 × 3 + 5 × 4] m2
= (30 + 24 + 20) m2
= 74 m2
Now Cost of white-washing per m2 area = Rs 7.50
So Cost of white-washing 74 m2 area = Rs (74 × 7.50)
= Rs 555
Answered by
2
Answer:
144 sq. m
Step-by-step explanation:
Area to be coverd with tin= Lateral surface area+base area
2(l+b)×h+ l×b
2(8+5)×4+(8×5)
2×13×4+40
104+40
144 m^2
Therefore 144 square metre of tin will require
Attachments:
Similar questions