Question

how many males of atom do in the following contain.(a)180g of Aluminium (b)160g of ferrous
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Answer 1

Answer:

No. of moles.of aluminium is equal to mass.divided by molar mass.multiply by avogadro's no.

no.of mole of aluminium is equal to 180g divided by 180g per mol multiply by 6.02 into ten raise to power -23

so there ate 6.02 into yen raise to power -23 are no. of moles present in 180g of aluminium