Question

How many many moles of Na2 Co3 are present in 212g of it

Answer 1

Answer:

2 moles

Explanation:

number of moles=given mass÷molar mass

molar mass=(23×2) +12 + (16×3)= 106

number of moles=212÷106=2 moles of Na2CO3

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Answer 2

Answer:

$as \: we \: know \: \\ moles = \frac{given \: weight}{molecular \: weight} \\ so \: the \: molecular \: weight \: of \: na2co3 \: = \frac{106g}{mol} \\ therefore \: moles \: = \frac{212}{106} = 2 moles$

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