Question

How many meiotic division are required to form 400 seeds of pea?

Answer 1

Answer:

500 meiotic divisions are required to form 400 seeds of pea.

Explanation:

For formation of one female gamete, one meiotic division is required.

So, 400 female gametes are produced after 400 meiotic divisions.

For formation of four male gametes, one meiotic division is required.

So, 400 male gametes are are produced after 100 meiotic divisions.

Therefore,for 400 seeds of pea to be produced, (400 female and 400 male gametes are essential), 400 + 100 = 500 meiotic divisions are required.

Answer 2

Answer:

Meiosis takes place in the megaspore and microspore mother cells during sexual reproduction of angiosperms.

To form 400 seeds of pea, 400 female and 400 male gametes are required.

Each microspore mother cell forms four microspores, and each of them develop pollen grains.

To produce 400 male gametes, we need 100 meiotic divisions.

Apart from that, each megaspore mother cell forms one female gamete.

So, to produce 400 female gametes, we need 400 meiotic divisions.

Finally, the total number of meiotic divisions required to form 400 seeds of pea, we require 100+400=500 meiotic divisions.