Question

How many meiotic divisions will be required to produce 88 viable seeds ?

Answer 1

There are 4 meiotic divisions will be required to produce 88 viable seeds.

Explanation:

• Ovule contains the female gametophyte or the embryo sac. Each ovule usually contains only one embryo sac.
• Each embryo sac is formed by meiotic division of the diploid mother cell.
• The result of a meiotic division is 4 haploid cells, in most cases, of the 4 haploid cells formed, three degenerate and one develops into the embryo sac.
• Therefore, to produce 88 viable embryo sacs 88 meiotic divisions are required.
• The one division can require 4 ovules to degenerate three. So, the correct answer is '88'.

To know more about

An angiospermic plant has to produce 88 viable ovules. How many meiotic division will be needed to produce equal numbers of female gametophyte by this plant. a- 88 b- 22 c- 44 d-132

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