Math, asked by sona1901, 1 year ago

How many men will bw required to plough 80 acres of land in 15 days if 12 men requires 4 days to plough 16 aceres of land?

Answers

Answered by KhanLuqman
1

Answer:

16 men would be required to plough 80 acres in 15 days

Step-by-step explanation:

First of all we have to find that how much acres one man can plough

so divide 16 by 12 which equals to 1.33

Thus one man would plough 1.33 acres in 4 days and thus in 15 days he would plough (15/4) × 1.33 = 5 acres

HENCE one man would plough 5 acres in 15 days THUS two men would plough 10 acres and so the men required to plough 80 acres would 80/5 = 16

Answered by halamadrid
0

16 men will be required to plow 80 acres of land in 15 days.

Given:

2 men require 4 days to plow 16 acres of land.

To Find:

The number of men required to plow 80 acres of land in 15 days.

Solution:

We are given that 12 men require 4 days to plow 16 acres of land.

We need to find how many men will be required to plow 80 acres of land in 15 days.

Assume that the required number of men = x.

Now let us represent this data in tabular form:

Area No. of men No. of days

80                   x                      15

16                   12                      4

We know that a greater number of men will be required to plow a bigger land.

∴ There the number of men and the area of land to plow are directly proportional.

Also, if more men are present, the work will be completed quickly.

∴ There the number of men and the number of days required to plow the land are inversely proportional.

Writing the above statements into an equation, we have:

80:16 :: x:12 :: 4:15

\frac{80}{16} = \frac{x}{12} =\frac{4}{15}

⇒ 80x12x4 = 16× x × 15

⇒ x = 16

Hence, 16 men will be required to plough 80 acres of land in 15 days.

#SPJ3

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