Question

how many metres of cloth 5dm wide will cover the table whose area is 36sq metres?​

Answer 1

ans:r=7m,h=24m,l=?

r=7m,h=24m,l=?l

r=7m,h=24m,l=?l 2

r=7m,h=24m,l=?l 2 =r

r=7m,h=24m,l=?l 2 =r 2

r=7m,h=24m,l=?l 2 =r 2 +h

r=7m,h=24m,l=?l 2 =r 2 +h 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l=

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25m

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl=

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 7

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2 ∴ length=

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2 ∴ length= width

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2 ∴ length= width550m

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2 ∴ length= width550m 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2 ∴ length= width550m 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2 ∴ length= width550m 2 =

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2 ∴ length= width550m 2 = 5

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2 ∴ length= width550m 2 = 5550m

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2 ∴ length= width550m 2 = 5550m 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2 ∴ length= width550m 2 = 5550m 2

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2 ∴ length= width550m 2 = 5550m 2 =110m

r=7m,h=24m,l=?l 2 =r 2 +h 2 =7 2 +24 2 =49+576=625∴l= 625 =25mArea of canvas used=CSA of conical tent∴ CSA of a cone=πrl= 722 ×7m×25m=550m 2 Area of canvas=550m 2 Length× width=550m 2 ∴ length= width550m 2 = 5550m 2 =110m∴ Length of canvas used=110m.