Question

How many milligrams of NaOH is required for 200 mL of 0.01% solution?​

Answer 1

Answer:

285.48 g

how many grams of water must be added to 200 ml of NaOH solution in order to have a solution with a specific gravity of 1.157, 13.55%? (Specific gravity= 1.32, 28.83%). the answer is 285.48 g

Answer 2

Given:-

→ Volume of solution = 200 mL

→ Concentration of solution = 0.01%

To find:-

→ Mass of NaOH [ in miligrams ]

Solution:-

In this case, we can understand that NaOH is the solute and we have the volume of solution and concentration [ mass/volume % ].

Let the required mass of NaOH be 'x' grams.

Now we know that:-

Concentration [mass/volume % ]

= Mass of solute/Vol.of solution × 100

By substituting values in the above formula, we get :-

=> x/200 × 100 = 0.01

=> 100x = 0.01(200)

=> 100x = 2

=> x = 2/100

=> x = 0.02g

Now, let's convert the mass of NaOH from grams to miligrams.

=> 1g = 1000mg

=> 0.02g = 0.02(1000)

=> 20mg

Hence, the required mass of NaOH

is 20mg .