how many milliliters of 8M HCL would you need to prepare 500mL of 2M HCL?
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1. we multiply 500 ml to 2m.
500× 2m = volume ×8m
divided both sides of equation by 8m
so that this whole termed canceled from the right side of the equal sign.
500×2÷ 8= volume × 8÷8
1000 ÷ 8 = volume
we divided 1000 by 8
we get 125. so the volume = 125
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