How many milliliters of a 10.6 M NaOH solution are needed to prepare 0.715 L solution of NaOH with a concentration of 0.550 M?
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Answer:
The molarity of NaOH solution before dilution, M1 = 10.6 M
After dilution of NaOH,
Volume, V2 = 0.715 L
Concentration or molarity, M2 = 0.550 M
Let’s assume the volume before dilution is “V1”.
We know,
M1 * V1 = moles of solute = M2 * V2
⇒ 10.6 * V1 = 0.550 * 0.715
⇒ V1 = 0.3932 / 10.6 = 0.03709 L
⇒ V1 = 0.0370 * 1000 ml = 37.09 ml
Hence, 37.09 ml of NaOH is needed.
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