How many milliliters of pure acid must be added to 150 milliliters of a 40% solution of acid to obtain a 50% solution?
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Answered by
0
Answer:
acid + acid = acid
0.30*150 + 1*x = 0.40(150+x)
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30*150 + 100x = 40*150 + 40x
60x = 10*150
x = (1/6)150
x = 25 mm (amt of pure acid needed
Answered by
0
Answer:
300 milliliters of a solution contains 12% of salt.
Salt contain in 300ml solution = 12% of 300.
= (12/100)300
= 36ml
Total solution after adding pure water
= (200+300)ml
= 500ml
1 % of salt in resulting solution = (36/500)× 100
= 7.2%
Step-by-step explanation:
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