Question

how many millilitres of glycerol of density 1.26g/ml must be added to per kg of water to produce a solution with 4.85 mole pressure of C6H8O3​

Answer 1

Explanation:

HEY MATE

4.55 mole percent = 0.0455 mole fraction.So you want 0.0455 mole glycerin/kg water.Do you know what mole fraction is?mole fraction glycerin = moles gly/total moles where total moles = moles glycerin + moles water.moles water in 1 kg = 1000/molar massmoles glycerin = 0.0455mole fraction glycerin = 0.0455/(0.0455 + 55.5) = ??Convert 0.0455 moles glycerin to grams and convert grams to mL using the density.