Question

How many millilitres of water is added to change 100mL of pH = 2 solution into pH= 2.7 solution

Answer 1

Answer:

093848

Explanation:

this is the answer

093848

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Answer 2

The volume of water added to change the pH is 402ml.

Given:-

Volume 1 (v1) = 100ml

pH 1 = 2

pH 2 = 2.7

To Find:-

The volume of water added to change the pH.

Solution:-

We can Simply find out the volume of water added to change the pH by using the following method.

As

Volume 1 (v1) = 100ml

pH 1 = 2

pH 2 = 2.7

Volume 2 = v2 =?

Before going to the volume, first, we have to change the pH to the number of Hydrogen Ions.

$[H+] = {10}^{ - ph}$

$[H+] 1=c1 = {10}^{ - 2}$

$[H+] 2= c2 = {10}^{ - 2.7}$

Now, the number of moles of both solutions will be equal.

So,

$c1v1 = c2v2$

${10}^{ - 2} \times 100 = {10}^{ - 2.7} \times v2$

$1 = 0.00199 \times v2$

$v2 = \frac{1}{0.00199}$

$v2 = 502ml$

Now we have to calculate the change in volume by,

$∆v = v2 - v1$

$∆v = 502 - 100$

$∆v = 402ml$

Hence, The volume of water added to change the pH is 402ml.

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