How many minimum number of transistors (both p and n) are required to construct a CMOS AND gate?
Answers
The number of transistors required to implement an N-input logic gate is 2N.
Explanation:
CMOS is made up of NMOS and PMOS transistors.
A NOT gate requires 2 transistors, 1 NMOS and 1 PMOS.
A NAND gate requires 4, a 2 input AND requires 6.
A 4 input NAND gate requires 8 transistors, add an inverter and you have 10 transistors.
The number of transistors required to implement an N-input logic gate is 2N. The PDN network consists of two NMOS devices in series that conduct when both A and B are high. The PUN is the dual net- work, and consists of two parallel PMOS transistors.
Two MOS transistors are connected back-to-back in parallel with an inverter used between the gate of the NMOS and PMOS to provide the two complementary control voltages.
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