Chemistry, asked by Ujjwalraj703, 10 months ago

How many ml of 0.1 m hcl are required to react completely with 1 g mixture of na2c03 and nahco3 containing equimolar amounts of both?

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Answered by Anonymous

158 mL

Total mol of Hcl required to react with a mixture of NaHCO3 & Na2Co3= 2x 0.00526 + 0.00526= 0.01578 mol. Hence, 158 mL of 0.1 M of HCl is required to react completely with 1 g mixture of Na₂Co₃ and NaHCO₃, containing equimolar amounts of both.

Answered by malikmohaman

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