Question

How many mL of 0.200 M HCI are needed to neutralize 20.0 mL of 0.150 M Ba(OH)2?

Answer 1

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20ml=0.02letre

now,

M1V1=M2V2

M1=0.2

V1=?

M2=0.15

V2=0.02

Then,

0.2×v1=0.15×0.02

v1=0.02/0.2×0.15

v1=1/10×0.15

=0.015