How many ml of 0.48M NaOH will it take to neutralize 36ml of 0.40M HCI
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Explanation:
We have
M1 = 0.48 M
V1 = ?
M2 = 0.40 M
V2 = 0.036 L
we have, dilution formula
M1V1 = M2V2
V1 = M2V2/M1
= (0.40 x 0.036)/0.48
= 0.030 L
= 30 ml NaOH
Best of luck for your studies and exams.
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