How many mL of 0.5 N HCl acid will be required to completely neutralise 500ml of a 0.1N NaOH solution?
a)50 ml
b)100 ml
c)150 ml
d)200 ml
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1
Answer:
Option C is correct
Explanation:
First ,calculate the number of moles of NaOH present in 5 grams. The molar mass of NaOH is 40 g/mol.
Number of moles of NaOH in 5 gram =
40
5 =0.125 moles.
The moles of HCl needed = moles of NaOH
M 1 V 1 =M 2V 2
0.25×V
1=0.125×1000
V1 =0.25
0.125×1000 =500 mL
Option C is correct.
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