Question

How many mL of a 0.10 M FeSO4 solution are required to provide 0.35 g of FeSO4?

Answer 1

Answer:

Hope the pic helps

Explanation:

If the answer is correct plz mark it as BRAINLIEST

Answer 2

Answer:

0.23 L or 23 mL

Explanation:

Molarity = moles / volume of soln in lit.

Moles = mass / molecular mass

Molarity = mass / molecular mass / vol of soln in lit.

Molarity of feso4 = 0.10M

Mass (given) of feso4 = 0.35 gm

Mol mass of feso4 = 152gm

 

.0.10M = 0.35/152/vol of soln in lit.

Vol of soln = 0.0023/0.10

Vol of soln = 0.023 lit. Or 23 ml

Answer = 0.023lit. or 23 ml