Question

How many 'ml’of perhydrol is required to produce sufficient oxygen which can be used to completely convert 2 L of So2 gas to SO3 gas?
(1) 10 mL
(2) 5 mL
(3) 20 mL
(4) 30 mL​

Answer 1

AnSwer :-

perhydrol means 30% Solution of H$_2$O$_2$.

$\sf H_2O_2 \: decomposes \: as \: 2H_2O_2 \longrightarrow 2H_2O + O_2$

$\Large\star$Volume strength of 30% H$_2$O$_2$ Solution is 100 that means 1 mL of this Solution on decomposition give 100mL oxygen.

$\sf \: \: \: \: \: SO_2 + \frac{1}{2}O_2 \longrightarrow SO_3 \\ \sf \: \: \: \: \: \: \: 1L \: \: \: \: \: \: \: \: \: \: \: \frac{1}{2}L \: \: \: \: \: \: \: \: \: \: \: \: \: \: 1L \\ \sf \: \: \: \: \: \: \: 2L\: \: \: \: \: \: \: \: \: \: \:1L\: \: \: \: \: \: \: \: \: \: \: \: \:2L$

Since, 100mL of oxygen will be obtained by =1mL of H$_2$O$_2$.

1000mL of oxygen will be obtained by

$= \sf\dfrac{1}{100}\times 1000mL \: of \: H_2O_2$

$= \sf \: 10mL \: of \: H_2O_2$

thus, option (1) 10mL is correct.