How many ml of water would be displaced by 408 g of lead?
Answers
Answered by
20
Dendity of lead = 11.35g/cc.
408 grams therefore has a volume of (408/11.35) = 35.947cc.
It displaces 35.947cc of water, = 35.947 millilitres.
408 grams therefore has a volume of (408/11.35) = 35.947cc.
It displaces 35.947cc of water, = 35.947 millilitres.
Answered by
6
Hey dear,
● Answer -
36 ml
● Explaination -
- First we'll calculate volume of lead.
Volume = mass / density
V = 408 / 11.34
V = 35.98 cm^3
V = 36 ml
When lead is put in water, it will displace same volume of water.
i.e. 36 cm^3 = 36 ml
Therefore, 408 g of lead will displace 36 ml of water.
Hope this helps you...
● Answer -
36 ml
● Explaination -
- First we'll calculate volume of lead.
Volume = mass / density
V = 408 / 11.34
V = 35.98 cm^3
V = 36 ml
When lead is put in water, it will displace same volume of water.
i.e. 36 cm^3 = 36 ml
Therefore, 408 g of lead will displace 36 ml of water.
Hope this helps you...
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