Question

how many mole are present in 224ml at CH4​

Answer 1

Answer:

At STP P= 1 atm , T= 298.15K

Volume given= 0.224L

PV=nRT taking R=0.082 L atm/Mol .K

1*0.224=n*0.082*298.15

mole, n = 0.0091 at STP

point : If moles were asked at NTP then we could direct use 22.4L in one mole . mole = 0.224/22.4 = 0.01 at NTP

Answer 2

Answer:

here your answer

Explanation:

Mole = given litre / atomic litre

          (change ml to litre       1000ml = 1 litre)

        =0.224 / 17                                    [∵224ml = 0.224litre   and CH4=17 litre]

       0.032 mol

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