Question

How many mole are required to prepare 40 gm of H2SO4

Answer 1

Answer:

0.4 moles

Explanation:

no.of moles = mass given/ molar mass

Answer 2

$0.4081$ mole is required to prepare $40 gm$ of $H_2SO_4$.

Explanation:

The mass of a sample of a chemical compound divided by the amount of material in that sample, measured in moles, is the molar mass of that compound.

Given:

mass of $H_{2}SO_{4}=40 gm$

To find: number of moles required to prepare $40 gm$ of sulphuric acid.

We know that, molar mass of sulphuric acid is $98 g/mol$

The required formula to find number of moles is

$Number of mole=\frac{Given \space mass}{molar \space mass}$

Substitute the respective values in the above formula

$Number of moles=\frac{40}{98}$

Number of moles required to prepare $40 gm$ of sulphuric acid.  = $0.4081 moles.$