How many mole of an ideal gas will occupy 8.2L at 10 atm pressure and 127°C ?
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Answer:
800 ml
Explanation:
v1 = 600ml
t1 = 27°C = 300k
p1 = 1atm
and ...
v2 = ?
t2 = 27°C = 400k
p2 = 1 atm
now applying charles law
p1v1/t1 = p2v2 / t2
600/3 = x/400
2 = x/400 = 800ml
Hope it helps u !!
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